(4/3(x))^2+14=(2/3(x))^2+20

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Solution for (4/3(x))^2+14=(2/3(x))^2+20 equation: 



(4/3(x))^2+14=(2/3(x))^2+20

We move all terms to the left:

(4/3(x))^2+14-((2/3(x))^2+20)=0



Domain of the equation: 3x)^2!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3x)^2+20)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+4/3x)^2-((+2/3x)^2+20)+14=0

We calculate fractions


((+4*3x)^2)/3x^2*3x)^2+20))+(-((+2*3x)^2)/3x^2*3x)^2+20))+14=0

We calculate fractions

We do not support expression: x^6

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